(y^2-16)(2y+10)=0

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Solution for (y^2-16)(2y+10)=0 equation:


Simplifying
(y2 + -16)(2y + 10) = 0

Reorder the terms:
(-16 + y2)(2y + 10) = 0

Reorder the terms:
(-16 + y2)(10 + 2y) = 0

Multiply (-16 + y2) * (10 + 2y)
(-16(10 + 2y) + y2(10 + 2y)) = 0
((10 * -16 + 2y * -16) + y2(10 + 2y)) = 0
((-160 + -32y) + y2(10 + 2y)) = 0
(-160 + -32y + (10 * y2 + 2y * y2)) = 0
(-160 + -32y + (10y2 + 2y3)) = 0
(-160 + -32y + 10y2 + 2y3) = 0

Solving
-160 + -32y + 10y2 + 2y3 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-80 + -16y + 5y2 + y3) = 0

Ignore the factor 2.

Subproblem 1
Set the factor '(-80 + -16y + 5y2 + y3)' equal to zero and attempt to solve:

Simplifying
-80 + -16y + 5y2 + y3 = 0

Solving
-80 + -16y + 5y2 + y3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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